The ratio of acid strength of H O C N and H C N is about Given K a of H O C N = 1.2 × 10 – 4 and K a of H C N = 4.2 × 10 – 10

H + H O C N H + H C N = K a o f H O C N 1 / 2 K a o f H C N 1 / 2 = 1.2 × 1 0 - 4 4.2 × 1 0 - 10 1 / 2 = 535

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Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumpH of Strong and Weak Acids and BasesEasy2 minPYQ_2020

ChemistryEasysingle choice

The ratio of acid strength of $H O C N$ and $H C N$ is about

Given $K_{a}$ of $H O C N = 1.2 \times 10^{- 4}$ and $K_{a}$ of $H C N = 4.2 \times 10^{- 10}$

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Answer:

Solution:

$\frac{{[H^{+}]}_{H O C N}}{{[H^{+}]}_{H C N}} = \frac{{(K_{a} o f H O C N)}^{1 / 2}}{{(K_{a} o f H C N)}^{1 / 2}}$

$= {(\frac{1.2 \times 1 0^{- 4}}{4.2 \times 1 0^{- 10}})}^{1 / 2} = 535$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:pH of Strong and Weak Acids and Bases

⏱ 2mℹ️ Source: PYQ_2020

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