Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

The $K_{sp}$ of Mg $(OH)_{2}$ is $1 \times 1 0^{- 12} .$ A 0.01 M $MgC l_{2}$ solution will precipitate at what limiting pH value?

Answer:

9.00

Solution:

$K_{sp} = [M g^{2 +}] {[O H^{-}]}^{2}$

$[O H^{-}] = \sqrt{\frac{1 \times 1 0^{- 12}}{0.01}}$

$[O H^{-}] = 1 0^{- 5}$

$pOH = 5$

$pH = 9$

Stream:NTA_ABHYASSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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