Chemistry - Ionic Equilibrium Question with Solution | TestHub

$\text{Q}=\left[{\text{Pb}}^{2+}\right]{\left[{\text{Cl}}^{-}\right]}^2$
$=\left(\frac{300\times 0.134}{400}\right){\left(\frac{100\times 0.4}{400}\right)}^2=\frac{3\times 0.134}{4}(0.1{)}^2$
$\mathrm{Q}=1.005\times 10^{-3}$
Hence,$\mathrm{Q}>{\mathrm{K}}_{\mathrm{s}\mathrm{p}}$