The solubility (S) of a solute in water varies with temperature as given by $S = A e^{- Δ H / R T}, Δ H$ being the enthalpy of solution. For a given solute, variation of lnS with temperature is as shown in figure. The solute is expected to be

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lnS = lnA − ΔH RT Slope = − ΔH RT lnS vs 1 T graph with negative slope. So, Δ H > 0 Salts with water of crystallisation. i.e., C u S O 4 . 5 H 2 O .

Chemistry - Ionic Equilibrium Question with Solution | TestHub

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