Chemistry - Ionic Equilibrium Question with Solution | TestHub

As the volume is doubled, concentration would be half. The total$\left[{\text{H}}^{\text{+}}\right]$is obtained by addition of$\left[{\text{H}}^{\text{+}}\right]$from both acids.
$[{\mathrm{H}}^{+}]=\sqrt{\left({\mathrm{K}}_{\mathrm{a}1}{\mathrm{C}}_1+{\mathrm{K}}_{\mathrm{a}2}{\mathrm{C}}_2\right)}$
$=\sqrt{\left(2\times 10^{-5}\times \frac{0.1}{2}+6\times 10^{-5}\times \frac{0.1}{2}\right)}$
$=2\times 10^{-3}$
$\mathrm{p}\mathrm{H}=2.7$