Chemistry - Ionic Equilibrium Question with Solution | TestHub

Solubility of${\text{BaSO}}_4,\text{s}=\frac{2.42\times {10}^{-3}}{233}\left({\text{molL}}^{-1}\right)$
$=1.04\times 10^{-5}\left(\mathrm{m}\mathrm{o}\mathrm{l}{\mathrm{L}}^{-1}\right)$
${\text{BaSO}}_4\left(\text{s}\right)\rightleftharpoons \underset{\text{s}}{{\text{Ba}}^{2+}}\left(\text{aq}\right)+\underset{\text{s}}{{\text{SO}}_4^{2-}}\left(\text{sq}\right)$
${\mathrm{K}}_{\mathrm{s}\mathrm{p}}=\left[\mathrm{B}{\mathrm{a}}^{2+}\right]\left[\mathrm{S}{\mathrm{O}}_4^{2-}\right]={\mathrm{s}}^2$
$=(1.04\times 10^{-5}{)}^2$
$=1.08\times 10^{-10}\mathrm{m}\mathrm{o}{\mathrm{l}}^2{\mathrm{L}}^{-2}$