The dissociation constant of a substituted benzoic acid is 1 . 0 × 10 - 4 at 25 o C . The pH of 0.01 M solution of its sodium salt is

For a salt of a weak acid and strong base p H = 7 + 1 2 p K a + 1 2 l o g C = 7 + 1 2 − log 1 × 10 − 4 + 1 2 log 0.01 = 8 .

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Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumHydrolysis of SaltsEasy2 minPYQ_2020

ChemistryEasysingle choice

The dissociation constant of a substituted benzoic acid is $1.0 \times 10^{- 4}$ at $25^{o} C$ . The pH of 0.01 M solution of its sodium salt is

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Solution:

For a salt of a weak acid and strong base
$p H = 7 + \frac{1}{2} p K a + \frac{1}{2} l o g C$
$= 7 + \frac{1}{2} (- log 1 \times 10^{- 4}) + \frac{1}{2} log (0.01)$
$= 8 .$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Hydrolysis of Salts

⏱ 2mℹ️ Source: PYQ_2020

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