The pH of 0.5 M aqueous solution of H F K a = 2 × 1 0 - 4 is

K a = C α 2 2 × 10 4 = 0.5 × α 2 α = 2 × 10 - 2 ∴ H + = C α = 0.5 × 2 × 10 - 2 = 10 - 2 p H = 2

Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

The pH of 0.5 M aqueous solution of $H F$ $(K_{a} = 2 \times 1 0^{- 4})$ is

Answer:

Solution:

$K_{a} = C α^{2}$
$2 \times 10^{4} = 0.5 \times α^{2}$
$α = 2 \times 10^{- 2}$
$∴ [H^{+}] = C α = 0.5 \times 2 \times 10^{- 2} = 10^{- 2}$
$p H = 2$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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