Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumSolubility ProductEasy2 minPYQ_2020
ChemistryEasysingle choice

Calculate the solubility product ofCo2[Fe(CN)6]in water at25°C.
Given, conductivity of saturated solutions ofCo2[Fe(CN)6]is 2.06 ×  10 −6   Ω −1   cm −1 and that of water used is 4.1 ×  10 −7   Ω −1   cm −1 . The ionic molar conductivities ofCo2+and[Fe(CN)6]4-are 86.0 Ω  cm 2   mol −1 and 444.0  Ω −1   cm 2   mol −1 , respectively.

Options:

Answer:
A
Solution:

κCo2[Fe(CN)6]=2.06×10-6-0.41×10-6=1.65×10-6
ΛmCo2[Fe(CN)6]=2ΛmCo2++Λm[Fe(CN)6]4-
=2×86+444=616  Scm 2   mol −1
Λm=1000κc
c=2.7×10-6M
KspCo2[Fe(CN)6]=4c3=7.87×10-17M3.

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Solubility Product
⏱ 2mℹ️ Source: PYQ_2020

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