Dissociation constants of C H 3 C O O H and N H 4 O H in aqueous solution are are almost same ( 1 0 - 5 ) . If pH of a C H 3 C O O H solution is 3, what will be the pH of N H 4 O H ?

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pH of C H 3 C O O H Sol = 3 So [ H 3 O + ] = c × K a = 1 0 - 3 or 1 0 - 3 = c × 1 0 - 5 or c = 1 0 - 1 M K b = K a = 1 0 - 5 pH of 1 0 - 3 M Solution of N H 4 O H [ O H - ] = c × K b = 1 0 - 1 × 1 0 - 5 = 1 0 - 3 pOH = 3 or p H = 14 - 3 = 11

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