Chemistry - Ionic Equilibrium Question with Solution | TestHub

After mixing,
$\left[{\mathrm{A}\mathrm{g}}^{+}\right]=\frac{1}{2}\mathrm{ }\times \mathrm{ }{10}^{–4}=5\mathrm{ }\times \mathrm{ }{10}^{–\mathrm{5 }}\mathrm{M}$
$\left[{\mathrm{C}\mathrm{l}}^{–}\right]\mathrm{ }=\frac{1}{2}\times \mathrm{ }{10}^{–4}=5\mathrm{ }\times \mathrm{ }{10}^{–5}\mathrm{ }\mathrm{M}$
${\text{Q}}_{\text{sp}}=\left[{\text{Ag}}^{\text{+}}\right]\left[{\text{Cl}}^{–}\right]={\left(5\times {10}^{–5}\right)}^2=2.5\times {10}^{–9}$
Since,${\text{Q}}_{\text{sp}}>{\text{K}}_{\text{sp}}\to$precipition takes place