Chemistry - Ionic Equilibrium Question with Solution | TestHub

$\underset{\mathrm{B}\mathrm{a}(\mathrm{O}\mathrm{H}{)}_2}{{\mathrm{N}}_1{\mathrm{V}}_1}=\underset{\mathrm{m}\mathrm{i}\mathrm{x}\mathrm{t}\mathrm{u}\mathrm{r}\mathrm{e}}{{\mathrm{N}}_2{\mathrm{V}}_2}$
[Normality of solution of$\mathrm{B}\mathrm{a}(\mathrm{O}\mathrm{H}{)}_2=2\times$molarity, as its mol. wt = 2 x eq. wt as n- factor is 2 for it. ]
$0.01\times 2\times 50={\mathrm{N}}_2\times (50+50)$(as it is assumed as 100% ionised).
${\mathrm{N}}_2=\frac{0.01\times 100}{100}=0.01$$\mathrm{N}$
$\mathrm{p}\mathrm{O}\mathrm{H}=-\mathrm{l}\mathrm{o}\mathrm{g}\left[\mathrm{O}{\mathrm{H}}^{-}\right]=-\mathrm{l}\mathrm{o}\mathrm{g}10^{-2}=2\mathrm{l}\mathrm{o}\mathrm{g}10$
$\mathrm{p}\mathrm{O}\mathrm{H}=2$
$\mathrm{p}\mathrm{H}+\mathrm{p}\mathrm{O}\mathrm{H}=14$
$\mathrm{p}\mathrm{H}+2=14$
$\mathrm{p}\mathrm{H}=12$