Chemistry - Ionic Equilibrium Question with Solution | TestHub

${\mathrm{K}}_2\mathrm{S}{\mathrm{O}}_4,\mathrm{K}\mathrm{C}\mathrm{l}$and$\mathrm{N}\mathrm{a}\mathrm{N}{\mathrm{O}}_3$are the salts of strong acids and strong basis, so they do not undergo hydrolysis.$\mathrm{C}{\mathrm{H}}_3\mathrm{C}\mathrm{O}\mathrm{O}\mathrm{K}$is salt of weak acid,$\mathrm{C}{\mathrm{H}}_3\mathrm{C}\mathrm{O}\mathrm{O}\mathrm{H}$and strong basic NaOH, so it hydrolyses to give basic solution (i.e.,$\mathrm{p}\mathrm{H}>7$)
${\text{CH}}_{\text{3}}{\text{COO}}^{-}\text{K}\text{+}\text{HOH}\to \underset{\left(\text{weak}\text{acid}\right)}{{\text{CH}}_{\text{3}}\text{COOH}}\text{+}\underset{\left(\text{strong}\text{base}\right)}{\text{KOH}}$