Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumSolubility ProductHard2 minPYQ_2018

ChemistryHardnumerical

The solubility of a salt of weak acid at $p H = 3 i s Y \times 1 0^{- 3} m o l L^{- 1}$ . The value of $Y$ is ____. (Given that the value of solubility product of $AB (K_{sp}) = 2 \times 10^{- 10}$ , and the value of ionization constant of $HB (Ka) = 1 \times 10^{- 8}$ )

Answer:

4.47

Solution:

$S = \sqrt{K_{sp} (\frac{[H^{+}]}{K_{a}} + 1)} = \sqrt{2 \times 10^{- 10} (\frac{10^{- 3}}{10^{- 8}} + 1)} ≃ \sqrt{2 \times 10^{- 5}}$
$= 4 .47 \times 10^{- 3} M$ .

Stream:JEE_ADVSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Solubility Product

⏱ 2mℹ️ Source: PYQ_2018

Doubts & Discussion

Loading discussions...