Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumHydrolysis of SaltsMedium2 minPYQ_2016

ChemistryMediumsingle choice

The percentage hydrolysis of $0.15 M$ solution of ammonium acetate, $K_{a}$ for $CH_{3} COOH$ is $1.8 \times 1 0^{- 5}$ and $K_{b}$ for $NH_{3}$ is $1.8 \times 1 0^{- 5}$

Options:

Answer:

Solution:

$α = \frac{K _{w}}{K _{a} \times K _{b}} = \frac{1 \times 1 0 ^{- 14}}{1.8 \times 1 0 ^{- 5} \times 1.8 \times 1 0 ^{- 5}} = 0.55$

Stream:BITSATSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Hydrolysis of Salts

⏱ 2mℹ️ Source: PYQ_2016

Doubts & Discussion

Loading discussions...