Chemistry - Ionic Equilibrium Question with Solution | TestHub

${\mathrm{HClO}}_4$ is the strongest acid among $\mathrm{HClO}$, ${\mathrm{HClO}}_2,{\mathrm{HClO}}_3$ and ${\mathrm{HClO}}_4$ as more the number of oxygen atoms attached, more is the acidity of the molecule order of acidity is : $$\mathrm{HClO}<{\mathrm{HClO}}_2<{\mathrm{HClO}}_3<{\mathrm{HClO}}_4$$ So the conjugate base order will be just the reverse: $${\mathrm{ClO}}^{-}>{\mathrm{ClO}}_2^{-}>{\mathrm{ClO}}_3^{-}>{\mathrm{ClO}}_4^{-}$$