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Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasIdeal Gas Equation & problemsMedium2 minQB

ChemistryMediumsingle choice

A quantity of methane gas occupies a volume of 25.0 mL at a certain temperature and pressure. What volume would three times this mass of methane occupy at half the absolute temperature if the pressure were one-sixth that of the original gas?

Options:

Answer:

Solution:

$V$ is proportional to nT/ $P$ .

$V_{2}$ / $V_{1}$ = ( $n_{2}$ / $n_{1}$ )( $T_{2}$ / $T_{1}$ )( $P_{1}$ / $P_{2}$ ) = (3)(1/2)(6) = 9.

$V_{2}$ = 9 x 25.0 = 225 mL.

Answer: (D).

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Ideal Gas Equation & problems

⏱ 2mℹ️ Source: QB

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