A fixed amount of gas is cooled from 400 K to 100 K at constant volume and then compressed isothermally to one fourth of its volume. Which option gives the final to initial ratio of (collisions made b

Question

A fixed amount of gas is cooled from 400 K to 100 K at constant volume and then compressed isothermally to one fourth of its volume. Which option gives the final to initial ratio of (collisions made by a molecule per second, mean free path)?

TestHub · Accepted Answer

Step 1 (constant V, T from 400 K to 100 K): N is unchanged. Collisions per molecule per second is proportional to $N T$ , so it becomes $100/400 = 1/2$ . Mean free path is unchanged.

Step 2 (T constant, V becomes V/4): N becomes 4N, so collisions per molecule per second becomes 4 times and mean free path becomes 1/4.

Overall: collisions per molecule per second (1/2)(4) = 2 times; mean free path = 1/4.

Answer: (D).

Chemistry - Ideal Gas Question with Solution | TestHub

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