Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasCollision ParametersMedium2 minQB

ChemistryMediumsingle choice

In a rigid container $NH_{3}$ is kept at certain temperature where its pressure is found to be $P_{1}$ . If on doubling the temperature, it is completely dissociated into $N_{2}$ and $H_{2}$ . At these conditions, pressure of mixture is found to be $P_{2}$ . Find ratio of $P_{2}$ to $P_{1}$

Options:

Answer:

Solution:

$\frac{P _{1}}{n _{1} T _{1}} = \frac{P _{2}}{n _{2} T _{2}}$

$\frac{P _{1}}{a \times T} = \frac{P _{2}}{2 \times a \times 2 T}, \frac{P _{2}}{P _{1}} = \frac{4}{1}$

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Collision Parameters

⏱ 2mℹ️ Source: QB

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