Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasKinetic Theory of GasesHard2 minQB
ChemistryHardmatching list

Column I compares the root mean square speeds of two gas samples (first : second). Match each case with the statements in Column II that are true (the same ratio holds for the most probable speeds) (a Column I entry may match more than one Column II entry):

Column I (Comparison)

Column II (Statement)

(P) at 100 at 200 K

(1) the two speeds are equal

(Q) at 800 at 200 K

(2) the first is faster

(R) at 100 at 400 K

(3) the first is slower

(S) at 100 at 400 K

(4) the ratio is or

 

(5) the same ratio holds for the most probable speeds

Choose the option with the correct matching:

Options:

Answer:
B
Solution:

Speed is proportional to ; compare T/M.

(P) 100/2 = 50 and 200/4 = 50: equal. Both speeds scale the same way: 1, 5.

(Q) 800/32 = 25 and 200/16 = 12.5: ratio , first faster: 2, 4, 5.

(R) 100/16 = 6.25 and 400/32 = 12.5: ratio , first slower: 3, 4, 5.

(S) 100/64 = 1.5625 and 400/16 = 25: ratio 1 : 4, first slower: 3, 5.

Correct matching: P to 1,5; Q to 2,4,5; R to 3,4,5; S to 3,5. Answer: (B).

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Kinetic Theory of Gases
⏱ 2mℹ️ Source: QB

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