How many moles of H 2 O are in the system?

Total moles initially = ((570/760) × 1.642)/(0.0821 × 300) = 0.05 mol. Gas remaining (CO 2 + N 2 ) = 0.035 mol. n(H 2 O) = 0.05 - 0.035 = 0.015 mol. Hence (b).

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Passage / Comprehension

The apparatus shown consists of three temperature jacketed 1.642 l bulbs connected by stopcocks. Bulb A contains a mixture of H₂O(g), CO₂(g) and N₂(g) at 27^°C and a total pressure of 570 mm Hg. Bulb B is empty and held at a temperature of -73^°C. Bulb C is also empty and is held at a temperature of -193^°C. The stopcocks are closed and the volume of the lines connecting the bulbs is zero. CO₂ sublimes at -78^°C and N₂ boils at -196^°C. Neglect the volume of any solid, if formed.

How many moles of H₂O are in the system?

Options:

Answer:

Solution:

Total moles initially = ((570/760) × 1.642)/(0.0821 × 300) = 0.05 mol. Gas remaining (CO₂ + N₂) = 0.035 mol. n(H₂O) = 0.05 - 0.035 = 0.015 mol. Hence (b).

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Problems related with container/piston/SPM

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