Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasKinetic Theory of GasesMedium2 minQB
ChemistryMediummatching list
Match Column I with Column II
Column I | Column II |
|---|---|
A) H2 gas at 300 K | P) Maximum translational KE per mol |
B) CH4 gas at 400 K | Q) Maximum translational KE per gram |
C) O2 gas at 900 K | R) Minimum translational KE per mol |
D) He gas at 600 K | S) Minimum translational KE per gram |
Options:
Answer:
C
Solution:
Translational KE per mol = (3/2)RT, so it depends only on T: largest for O2 at 900 K (C→P) and smallest for H2 at 300 K (A→R). Per gram it is (3/2)RT/M, i.e. ∝ T/M: H2: 300/2 = 150; CH4: 400/16 = 25; O2: 900/32 ≈ 28.1; He: 600/4 = 150. Maximum per gram is shared by H2 and He (A,D→Q); minimum per gram is CH4 (B→S). Hence A→Q,R; B→S; C→P; D→Q.
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Kinetic Theory of Gases
⏱ 2mℹ️ Source: QB
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