Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasKinetic Theory of GasesEasy2 minQB
ChemistryEasysingle choice
The RMS speed of a sample of N₂O₄ gas is 'v' m/s at 27°C. When the temperature is increased to 327°C, all the N₂O₄ molecules are dissociated into NO₂ molecules. What is the RMS speed of new gas sample?
Options:
Answer:
D
Solution:
v = √(3R(300)/92) (N₂O₄, M = 92). New: NO₂, M = 46, T = 600 K. Ratio (v')/v = √((600/46)/)300/92 = √((600 × 92)/)46 × 300 = √(4) = 2. So v' = 2v. Confirms Ans (d) 2v m/s.
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Kinetic Theory of Gases
⏱ 2mℹ️ Source: QB
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