An unspecified quantity of an ideal gas was at initial pressure of 4 atm and temperature of 300 K. The gas is expanded at 300 K until the volume has increased by 50% of the initial value. Next, the qu

Question

An unspecified quantity of an ideal gas was at initial pressure of 4 atm and temperature of 300 K. The gas is expanded at 300 K until the volume has increased by 50% of the initial value. Next, the quantity of the gas in the vessel is increased by 25% of the initial value while the volume is maintained constant. Finally, the temperature is adjusted at constant volume until the gas pressure is again 4 atm. What is the final temperature, in kelvin?

Answer:

360

Solution:

Step 1 (isothermal, V -> 1.5V): P = 4/1.5 atm.

Step 2 (constant V, n -> 1.25n): P = (4/1.5) × 1.25 = 3.333 atm at 300 K.

Step 3 (constant V, heat until P = 4 atm): T = 300 × 4/3.333 = 360 K ⇒ 0360.

TestHub · Accepted Answer

Step 1 (isothermal, V -> 1.5V): P = 4/1.5 atm.

Step 2 (constant V, n -> 1.25n): P = (4/1.5) × 1.25 = 3.333 atm at 300 K.

Step 3 (constant V, heat until P = 4 atm): T = 300 × 4/3.333 = 360 K ⇒ 0360.

Chemistry - Ideal Gas Question with Solution | TestHub

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