Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasProblems related with container/piston/SPMMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
A glass tube AD of uniform cross-section of length 100 cm contains two columns of air (assume ideal behaviour) AB and CD, separately by a column of mercury (BC) of length 20 cm. When the tube is horizontal, AB = 20 cm and CD = 60 cm. When the tube is held vertically with the end 'A' up, the mercury column moves down 10 cm.
What is the pressure of air in the air columns, when the tube was horizontal?
Options:
Answer:
B
Solution:
Horizontal: PAB = PCD = P0. Vertical (A up): PAB' = P0 × 20/30 = 2P0/3; PCD' = P0 × 60/50 = 1.2P0. Balance: PCD' = PAB' + 20 ⇒ 1.2P0 - 0.667P0 = 20 ⇒ P0 = 37.5 cm Hg. Hence (b).
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Problems related with container/piston/SPM
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
