A gaseous mixture of three gases A, B and C has a pressure of 10 atm. The total number of moles of all the gases is 10. If the partial pressures of A and B are 3.0 and 1.0 atm, respectively, and if C

Question

A gaseous mixture of three gases A, B and C has a pressure of 10 atm. The total number of moles of all the gases is 10. If the partial pressures of A and B are 3.0 and 1.0 atm, respectively, and if C has molecular mass of 2.0, what is the mass of C, in g, present in the mixture?

Options:

Answer:

C

Solution:

p_C = 10 - 3 - 1 = 6 atm, so x_C = 6/10 = 0.6 and n_C = 0.6 × 10 = 6 mol. Mass of C = 6 × 2.0 = 12 g. Confirms Ans: (c) 12.

TestHub · Accepted Answer

p C = 10 - 3 - 1 = 6 atm, so x C = 6/10 = 0.6 and n C = 0.6 × 10 = 6 mol. Mass of C = 6 × 2.0 = 12 g. Confirms Ans: (c) 12.

Chemistry - Ideal Gas Question with Solution | TestHub

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