If for two gases of molecular weights M A and M B at temperature T A and T B , T A ·M B = T B ·M A , then which property has the same magnitude for both the gases?

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T A M B = T B M A ⇒ T A /M A = T B /M B . RMS speed u rms = √(3RT/M), so equal T/M gives equal RMS speeds. KE per mole (3/2RT) differs since T A ≠ T B in general; density and pressure depend on n, V as well and need not match. Confirms Ans (d) RMS speed.

Chemistry - Ideal Gas Question with Solution | TestHub

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