The average velocity of CO 2 at T K is 9 × 1 0 4 cm s − 1 . The value of T is

C a vg = π M 8 RT 9 × 1 0 4 = 3.14 × 44 8 × 8.314 × 1 0 7 × T [ value of R = 8.314 × 1 0 7 er g K − 1 m o l − 1 ], we can solve for T : On solving, T = 1682.55 K .

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The average velocity of $CO_{2}$ at T K is $9 \times 1 0^{4} cm s^{- 1}$ . The value of T is

Options:

Answer:

Solution:

$C_{a vg} = \frac{8 RT}{π M}$

$9 \times 1 0^{4} = \frac{8 \times 8.314 \times 1 0 ^{7} \times T}{3.14 \times 44}$

[ value of $R = 8.314 \times 1 0^{7} er g K^{- 1} m o l^{- 1}$ ], we can solve for $T$ :

On solving, $T = 1682.55 K$ .

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Kinetic Theory of Gases

⏱ 2mℹ️ Source: QB

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