Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasMaxwell's Distribution LawMedium2 minQB

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Passage / Comprehension

$C$ = the molecular speed (in meters per second), $f (C)$ = fraction of molecules with speed $C$ . For example, if $f (C) \times 1 0^{5} = 50$ , then $f (C) = 0.00050$ . These questions are based on the adjacent plot, which shows the Maxwell-Boltzmann Distribution of molecular speeds for nitrogen gas N₂ at $1000 K$ .

If carbon dioxide, $CO_{2}$ , were substituted for the nitrogen gas at 1000 K , the most probable speed of the molecules of $CO_{2}$ would be

Options:

Answer:

Solution:

The correct answer is (B) lower than that for N₂.

Formula: The most probable speed of a gas molecule is given by $v_{m p} = \frac{2 RT}{M}$ .

Relationship: At a constant temperature ( $T = 1000 K$ ), speed is inversely proportional to the square root of molar mass ( $v_{m p} \propto \frac{1}{M}$ ).

Comparison: The molar mass of CO₂ ( $44 g / m o l$ ) is greater than that of N₂ ( $28 g / m o l$ ).

Conclusion: Since CO₂ is heavier, its most probable speed will be lower than that of N₂.

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Maxwell's Distribution Law

⏱ 2mℹ️ Source: QB

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