Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasGraham's Law of Diffusion/EffusionMedium2 minQB

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Passage / Comprehension

Diffusion refers to the process of mixing of gases. Effusion is passage of gas through the hole into vacuum. According to Graham's law rate of diffusion of a gas is inversely proportional to the square root of the density of the gas.

In a vessel a mixture of $CH_{4}$ and HBr is present. If initial rates of effusion ratio for $CH_{4}$ and HBr is $4.5 : 1$ , at certain temperature, then mole fraction of HBr in the initial mixture is

Options:

Answer:

Solution:

$\frac{r _{CH_{4}}}{r _{HB_{r}}} = \frac{n _{CH_{4}}}{n _{HBr}} \frac{m _{HBr}}{m _{CH_{4}}}$

$\frac{4.5}{1} = \frac{n _{CH_{4}}}{n _{HBr}} \frac{81}{16}$

$\frac{n _{CH_{4}}}{n _{HBr}} = 4.5 \times \frac{4}{9} = 2$

∴ mol fraction of $HBr = \frac{1}{3} = 0.34$

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Graham's Law of Diffusion/Effusion

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