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4 g of $H_{2}$ and 32 g of $SO_{2}$ are present in a gaseous mixture at N.T.P. The partial pressure of $H_{2}$ is

Answer:

Solution:

$\frac{P _{H_{2}} = \frac{4}{2} \frac{RT}{V}}{P _{SO_{2}} = \frac{32}{64} \frac{RT}{V}} \Rightarrow P_{H_{2}} = 4 P_{SO_{2}}$ .

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Ideal Gas Equation & problems

⏱ 2mℹ️ Source: QB

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