Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasGraham's Law of Diffusion/EffusionMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
The leak rate, -dp/dt, of a gas is directly proportional to the difference in pressure of the gas in the cylinder and the external pressure. Some ideal gas is taken in a cylinder of 10 l capacity at 20 atm and 300 K. The proportionality constant is k = 10-3 s-1. The constant external pressure is 1 atm. (ln 38 = 3.6, ln 2 = 0.7, ln 10 = 2.3)
In what time, the pressure of gas in the cylinder becomes 2 atm?
Options:
Answer:
A
Solution:
p - 1 = 19e-kt with k = 10-3 s-1. For p = 2 atm: 1 = 19e-0.001t, so 0.001t = ln 19 = ln(38/2) = 3.6 - 0.7 = 2.9, giving t = 2900 s. Hence Ans (a).
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Graham's Law of Diffusion/Effusion
⏱ 2mℹ️ Source: QB
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