Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasIdeal Gas Equation & problemsEasy2 minQB
ChemistryEasysingle choice
An ideal gas is initially at temperature T and volume V. Its volume increases by ΔV due to an increase in temperature of ΔT, pressure remaining constant. The quantity δ = Δ V/(VΔ T) varies with temperature as
Options:
Answer:
C
Solution:
At constant pressure V/T is constant, so Δ V/Δ T = V/T, giving δ = (Δ V)/(VΔ T) = 1/T. This falls hyperbolically with rising temperature - the decreasing curve of graph (c). Matches (c).
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Ideal Gas Equation & problems
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