On a certain day the vapour pressure is 24 mm of Hg for water vapour in air at 300 K. The saturated vapour pressure is 26.463 mm. How many moles of water vapour per litre of air would be required to s

Question

On a certain day the vapour pressure is 24 mm of Hg for water vapour in air at 300 K. The saturated vapour pressure is 26.463 mm. How many moles of water vapour per litre of air would be required to saturate the air at this temperature?

TestHub · Accepted Answer

Extra pressure needed: ΔP = 26.463 − 24 = 2.463 mm Hg = 2.463/760 = 3.24 × 10 -3 atm. Moles per litre: n = Δ P,V/RT = 3.24 × 10 -3 × 1/(0.0821 × 300) = 1.32 × 10 -4 ≈ 1.3 × 10 -4 mol. Matches (a).

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