Suppose the inhaled air has partial pressure of water vapour of 5 mm Hg and exhaled air is nearly saturated at body temperature (310 K) with water vapour. The mass of water lost per day by a person as

Question

Suppose the inhaled air has partial pressure of water vapour of 5 mm Hg and exhaled air is nearly saturated at body temperature (310 K) with water vapour. The mass of water lost per day by a person assuming that the normal man breaths 10,000 litre per day. Saturated vapour pressure of water at 310 K is 45 mm Hg.

TestHub · Accepted Answer

ΔP = 45 - 5 = 40 mm = 40/760 atm. Moles of extra water vapour per day: n = ΔP·V/RT = (40/760 × 10000)/(0.0821 × 310) = 526.3/25.45 = 20.68 mol. Mass = 20.68 × 18 = 372.2 g. Confirms Ans: (b) 372.23 g.

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