Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasKinetic Theory of GasesMedium2 minQB
ChemistryMediumsingle choice
Which of the following gas will have the highest value for translational K.E. per g, at the same temperature?
Options:
Answer:
B
Solution:
Translational KE per mole = 3/2RT, the same for every gas at a given T. Per gram it is (3RT)/(2M), so the lightest gas wins. Molar masses: He = 4, CH4 = 16, N2 = 28 g/mol; helium is lightest. Confirms Ans (b) helium.
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Kinetic Theory of Gases
⏱ 2mℹ️ Source: QB
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