Sample of different gases are given at different conditions in column-I and column-II consist of translational kinetic energy of these gases at given conditions List - I List - II (P) 2 mole of SO 2 ( g ) at 700 K (1) Maximum K.E. per gram (Q) 1 mole of SO 3 ( g ) at 400 K (2) Maximum total K.E. (R) 4 Mole CH 4 ( g ) at 300 K (3) Minimum K.E. per gram (S) 2.5 Mole He ( g ) at 450 K (4) Minimum K.E. per molecule Correct code is :

KE = 2 3 ⋅ nRT KE = 2 3 × PV

Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasKinetic Theory of GasesMedium2 minQB

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Sample of different gases are given at different conditions in column-I and column-II consist of translational kinetic energy of these gases at given conditions

List - I	List - II
(P) 2 mole of $SO_{2} (g)$ at 700 K	(1) Maximum K.E. per gram
(Q) 1 mole of $SO_{3} (g)$ at 400 K	(2) Maximum total K.E.
(R) 4 Mole $CH_{4} (g)$ at 300 K	(3) Minimum K.E. per gram
(S) $2.5 Mole He (g)$ at 450 K	(4) Minimum K.E. per molecule

Correct code is :

Options:

Answer:

Solution:

$KE = \frac{3}{2} \cdot nRT$

$KE = \frac{3}{2} \times PV$

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Kinetic Theory of Gases

⏱ 2mℹ️ Source: QB

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