Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasGraham's Law of Diffusion/EffusionHard2 minQB
ChemistryHardmatching list

Gases in Column I effuse through the same small hole at the same temperature and pressure. Match each pair (first gas : second gas) with the statements in Column II that are true (a Column I entry may match more than one Column II entry):

Column I (Pair of gases)

Column II (Statement)

() : (D = 2 u)

(1) the first gas effuses faster

(Q) :

(2) ratio of rates = 2 : 1

() :

(3) for equal moles, the time ratio (first : second) is 1 : 2

(S) :

(4) ratio of rates = : 1

 

(5) the first gas effuses slower

Choose the option with the correct matching:

Options:

Answer:
C
Solution:

Rate is proportional to 1/, so rate ratio (first : second) = and time ratio = .

() = : 1. The lighter is faster: 1, 4.

(Q) = 2 : 1. is faster, and the time ratio is = 1 : 2: 1, 2, 3.

() = 1 : 2. is slower: 5.

(S) = 1.22 : 1. is faster, and the ratio is not listed: 1.

Correct matching: to 1,4; Q to 1,2,3; to 5; S to 1. Answer: ().

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Graham's Law of Diffusion/Effusion
⏱ 2mℹ️ Source: QB

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