Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasIdeal Gas Equation & problemsEasy2 minPYQ_2020

ChemistryEasysingle choice

One gram of hydrogen and 112 g of nitrogen are enclosed in two separate containers each of volume 5 L and at $27 ° C$ . If the pressure of the hydrogen is 1 atm, then the pressure of nitrogen would be

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Answer:

Solution:

Mol of $H_{2} = \frac{1}{2} m o l$
Mol of $N_{2} = \frac{112 g}{28 g m o l^{- 1}} = 4$ mol
$p_{1} V = n_{1} R T$ (Constant T and V)
$p_{2} V = n_{2} R T$
So $\frac{p_{1}}{p_{2}} = \frac{n_{1}}{n_{2}}$
i.e., $\frac{1 a t m}{p_{2}} = \frac{\frac{1}{2} m o l}{4 m o l}$
Hence, $p_{2} = 8$ atm.

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ideal GasSubtopic:Ideal Gas Equation & problems

⏱ 2mℹ️ Source: PYQ_2020

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