Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

At 400 K, the root mean square (rms) speed of a gas X (molecular weight = 40) is equal to the most probable speed of gas Y at 60 K. The molecular weight of the gas Y is

Answer:

4.00

Solution:

$v_{r m s}$ of $X = \sqrt{\frac{3 R T_{x}}{M_{x}}}; v_{m p}$ of Y $= \sqrt{\frac{2 R T_{y}}{M_{y}}}$

Given $v_{r m s} = v_{m p}$

$\sqrt{\frac{3 R T_{x}}{M_{x}}} = \sqrt{\frac{2 R T_{y}}{M_{y}}}$

$M_{y} = \frac{2 R T_{y} M_{x}}{3 R T_{x}} = \frac{2 \times 60 \times 40}{3 \times 400} = 4$

Stream:NTA_ABHYASSubject:ChemistryTopic:Ideal GasSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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