Chemistry - Ideal Gas Question with Solution | TestHub

Number of mol of gas$1=\frac{\mathrm{w}}{4}$

Number of mol of gas$2=\frac{\mathrm{w}}{40}$

Mole fraction of gas 1,${\mathrm{X}}_1=\frac{\frac{\mathrm{w}}{4}}{\frac{\mathrm{w}}{4}+\frac{\mathrm{w}}{40}}=\frac{10}{11}$

Partial pressure of gas 1$=$mol fraction of gas$1\times$Total pressure

$=\frac{10}{11}\times 1.1$atm = 1 atm