An air column closed in a tube sealed at one end by a $H g$ column having height $h$ . When the tube is placed with open end down, the height of the air column is $l_{1}$ . If the tube is turned so that its open end is at the top, the height of the air column is $l_{2} .$ What is the atmospheric pressure $(P_{0})$ -

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Let P 0 be the value at atmospheric pressure In case I: P g a s + h c m o f H g = P 0 c m o f H g In case ii P g a s = P 0 c m o f H g + h c m o f H g By applying Boyle's law between I & I I P 0 – h × l 1 = P 0 + h × l 2 or P 0 l 1 - h l 1 = P 0 l 2 + h l 2 or P 0 l 1 - l 2 = h l 1 + l 2 or P 0 = h l 1 + l 2 l 1 - l 2

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