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ChemistryIdeal GasMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

60 g of gaseous $C_{2} H_{6}$ are mixed with 28 g of carbon monoxide. The pressure of the resulting gaseous mixture is 3 atm. The partial pressure in atm. of $C_{2} H_{6}$ in the mixture is

Answer:

2.00

Solution:

Moles of $C_{2} H_{6} = \frac{60 g}{32 g / m o l} = 2 m o l$
moles of $C O = \frac{28 g}{28 g/mol} = 1 mol$
Mole fraction $C_{2} H_{6} = \frac{2}{2 + 1} = \frac{2}{3}$
Partial pressure of $C_{2} H_{6} = P_{t o t a l} \times$ Mole fraction of $C_{2} H_{6}$
$= 3 atm \times \frac{2}{3} = 2 atm$ .

Stream:NTA_ABHYASSubject:ChemistryTopic:Ideal GasSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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