At 27 o C, H 2 gas is leaked through a tiny hole into a vessel for 20 minutes. Another unknown gas, at the same temperature and pressure, as that of H 2 , is leaked through the same hole for 20 minute

Question

At 27 o C, H 2 gas is leaked through a tiny hole into a vessel for 20 minutes. Another unknown gas, at the same temperature and pressure, as that of H 2 , is leaked through the same hole for 20 minutes. After the effusion of the gases the mixture exerts a pressure of 6 atm. If H 2 is 0.7 mol and volume of vessel is 3 litre, calculate molecular weight of the unknown gas.

TestHub · Accepted Answer

Mole of gaseous mixture, n H 2 + Unknown gas = PV RT = 6 × 3 0.0821 × 300 = 0.7308 mole n (Unknown gas) = 0 .7308 − 0 .7 = 0 .0308 mole Mole of H 2 leaked Mole of unknown gas leaked = M Unknown M H 2 0 .7 0 .0308 = M 2 M = 1033 g mol − 1

Chemistry - Ideal Gas Question with Solution | TestHub

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