An ideal gas expands in volume from 1 × 1 0 -3 m 3 to 1 × 1 0 - 2 m 3 at 300 K against a constant pressure of 1 × 1 0 5 N m - 2 . The work done is

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ChemistryIdeal GasIdeal Gas Equation & problemsEasy2 minPYQ_2020

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An ideal gas expands in volume from $1 \times 1 0^{-3} m^{3}$ to $1 \times 1 0^{- 2} m^{3}$ at 300 K against a constant pressure of $1 \times 1 0^{5}$ $N m^{- 2}$ . The work done is

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Solution:

Work done due to change in volume against constant pressure is given as follows
$W = - P (V_{2} - V_{1}) = - 1 \times 1 0^{5}$ $N m^{- 2} (1 \times 1 0^{- 2} - 1 \times 1 0^{- 3})$ $m^{3}$
= –900 Nm
= –900 J

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ideal GasSubtopic:Ideal Gas Equation & problems

⏱ 2mℹ️ Source: PYQ_2020

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