Chemistry - Ideal Gas Question with Solution | TestHub

$\frac{{\text{r}}_1}{{\text{r}}_2}=\frac{{\text{V}}_1/\text{t}}{{\text{V}}_2/\text{t}}=\frac{{\text{V}}_1}{{\text{V}}_2}=\sqrt{\frac{{\text{M}}_2}{{\text{M}}_1}}$

Volume of 0.48 g of O₂at STP$=\frac{22400}{32}\times 0\text{.}48\text{ mL}$(32 g of O₂occupies 22400 mL at STP)

$\therefore \frac{{\text{V}}_{{\text{O}}_2}}{{\text{V}}_{{\text{CO}}_2}}=\sqrt{\frac{{\text{M}}_{{\text{CO}}_2}}{{\text{M}}_{{\text{O}}_2}}}=\sqrt{\frac{44}{32}}=1\text{.}173$

${\text{V}}_{{\text{CO}}_2}=\frac{{\text{V}}_{{\text{O}}_2}}{1\text{.}173}=\frac{22400}{32}\times \frac{0\text{.}48}{1\text{.}173}=286\text{.}5\text{ mL.}$