The average kinetic energy of one molecule of an ideal gas at 2 7 ∘ C and 1 atm pressure is

Average kinetic energy per molecule = 2 3 k T or 2 3 N 0 R T = 2 3 × 6.023 × 1 0 23 8.314 × 300 = 6.21 × 1 0 − 21 JK − 1 molecule − 1

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Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasKinetic Theory of GasesEasy2 minPYQ_2009

ChemistryEasysingle choice

The average kinetic energy of one molecule of an ideal gas at $2 7^{\circ} C$ and $1 atm$ pressure is

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Solution:

Average kinetic energy per molecule $= \frac{3}{2} k T$ or $\frac{3}{2} \frac{R}{N _{0}} T = \frac{3}{2} \times \frac{8.314}{6.023 \times 1 0 ^{23}} \times 300$ $= 6.21 \times 1 0^{- 21} JK^{- 1}$ molecule $^{- 1}$

Stream:VITEEESubject:ChemistryTopic:Ideal GasSubtopic:Kinetic Theory of Gases

⏱ 2mℹ️ Source: PYQ_2009

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