For the given hydrides:
(NH₃, H₂O, HF, H₂S, CH₄, BeH₂, MgH₂, SrH, NaH, BaH₂, CsH)

Find the value of $\frac{a \times b}{c + d}$
where:
$a$ = number of electron-rich hydrides
$b$ = number of polymeric solid hydrides without H-bonding
$c$ = number of electron-precise hydrides
$d$ = number of ionic hydrides

Question

For the given hydrides:

(NH₃, H₂O, HF, H₂S, CH₄, BeH₂, MgH₂, SrH, NaH, BaH₂, CsH)

Find the value of $\frac{a \times b}{c + d}$

where:

$a$ = number of electron-rich hydrides

$b$ = number of polymeric solid hydrides without H-bonding

$c$ = number of electron-precise hydrides

$d$ = number of ionic hydrides

TestHub · Accepted Answer

a b c d 4 + 1 4 × 2 ​ ​ = 4 = 2 = 1 = 4 = 5 8 ​ = 1.60 ​

Chemistry - Hydrogen and Its compound Question with Solution | TestHub