Degree of hardness (in terms of equivalents of ( CaCO 3 ) in ppm of a sample of water containing 24 mg of MgSO 4 ( mol . mass = 120 ) per kg of water is x . What is value of ( 5 X ) ?

Question

Degree of hardness (in terms of equivalents of ( CaCO 3 ​ ) in ppm of a sample of water containing 24 mg of MgSO 4 ​ ( mol . mass = 120 ) per kg of water is x . What is value of ( 5 X ​ ) ?

TestHub · Accepted Answer

120 g MgSO 4 ​ eq. to = 100 g CaCO 3 ​ 24 × 1 0 − 3 g " " " ​ = 120 100 ​ × 24 × 1 0 − 3 g CaCO 3 ​ ​ = 20 mg CaCO 3 ​ ​

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