Chemistry - Hydrogen and Its compound Question with Solution | TestHub

In hydrogen-oxygen fuel cell, following reactions take place to create potential difference between the two electrodes. $$\begin{array}{c}2{\mathrm{H}}_2(\mathrm{g})+4{\mathrm{OH}}^{-}(\mathrm{aq})\to 4{\mathrm{H}}_2\mathrm{O}(\mathrm{l})+4{\mathrm{e}}^{-}\\ {\mathrm{O}}_2(\mathrm{g})+2{\mathrm{H}}_2\mathrm{O}(\mathrm{l})+4{\mathrm{e}}^{-}\to 4{\mathrm{OH}}^{-}(\mathrm{aq})\\ \text{ Overall reaction }=2{\mathrm{H}}_2(\mathrm{g})+{\mathrm{O}}_2(\mathrm{g})\to 2{\mathrm{H}}_2\mathrm{O}(\mathrm{l})\end{array}$$ the net reaction is the same as burning (combustion) of hydrogen to form water.